Question

Q. A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is \(408 \mathrm{pm}\). The diameter of the metal atom is

A \(144 \mathrm{pm}\)
B \(204 \mathrm{pm}\)
C \(288 \mathrm{pm}\)
D \(408 \mathrm{pm}\)

Answer 1

Solution:
For \(F C C r=\frac{a}{2 \sqrt{2}}\)
So diameter \(=\frac{a}{\sqrt{2}}=\frac{408}{1.414}=288.5 \mathrm{pm}\)

Answer 2

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Answer 3

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