Question

$In$ the face-centred cubic lattice structure of gold the closest distance between gold atoms is ('a' being the edge ength of the cubic unit cell)
(A) $a \sqrt{2}$
(B) $\frac{a}{\sqrt{2}}$
(C) $\frac{a}{2 \sqrt{2}}$
(D) $2 \sqrt{2} \mathrm{a}$

Answer 1

Ans: (B)
 Closest distance between two gold atoms in fcc lattice of gold is $\frac{a}{\sqrt{2}}$. This is the distance between the corner atom and the closest face centre atom.

Answer 2

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