Question

Q. A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is $408 \mathrm{pm}$. The diameter of the metal atom is

A $144 \mathrm{pm}$
B $204 \mathrm{pm}$
C $288 \mathrm{pm}$
D $408 \mathrm{pm}$

Answer 1

Solution:
For $F C C r=\frac{a}{2 \sqrt{2}}$
So diameter $=\frac{a}{\sqrt{2}}=\frac{408}{1.414}=288.5 \mathrm{pm}$

Answer 2

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Answer 3

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