A thin convex lens is placed just above an empty vessel of depth \(80 \mathrm{~cm}\). The image of a coin kept at the bottom of the vessel is thus formed \(20 \mathrm{~cm}\) above the lens. If now water is poured in the vessel up to a height of \(64 \mathrm{~cm}\), what will be the approximate new position of the image. Assume that refractive index of water is \(4 / 3 .\)
(A) \(21.33 \mathrm{~cm}\) above the lens
(B) \(6.67 \mathrm{~cm}\) below the lens
(C) \(33.67 \mathrm{~cm}\) above the lens
(D) \(24 \mathrm{~cm}\) above the lens
Ans:(A)