Question

\(In\) the face-centred cubic lattice structure of gold the closest distance between gold atoms is ('a' being the edge ength of the cubic unit cell)
(A) \(a \sqrt{2}\)
(B) \(\frac{a}{\sqrt{2}}\)
(C) \(\frac{a}{2 \sqrt{2}}\)
(D) \(2 \sqrt{2} \mathrm{a}\)

Answer 1

Ans: (B)
 Closest distance between two gold atoms in fcc lattice of gold is \(\frac{a}{\sqrt{2}}\). This is the distance between the corner atom and the closest face centre atom.

Answer 2

cialis mail order usa <a href="https://ordergnonline.com/">oral tadalafil 20mg</a> buy ed medications online

Answer 3

is cialis generic <a href="https://ordergnonline.com/">cialis 10mg pills</a> where to buy otc ed pills