Question

How many moles of electrons will weigh one kilogram ?
(A) \(6.023 \times 10^{23}\)
(B) \(\frac{1}{9.108} \times 10^{31}\)
(C) \(\frac{6.023}{9.108} \times 10^{54}\)
(D) \(\frac{1}{9.108 \times 6.023} \times 10^{8}\)

Answer 1

Ans(D)

Hint: Mass of one mole electron \(=9.11 \times 10^{-31} \times 6.023 \times 10^{23} \mathrm{~kg}\)
$$
\therefore \text { No of moles }=\frac{1}{9.11 \times 6.023} \times 10^{8}
$$

Answer 2

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Answer 3

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