Question

If \(p, q\) are the roots of the equation \(x^{2}+p x+q=0\), then
(A) \(p=1, q=-2\)
(B) \(p=0, q=1\)
(C) \(p=-2, q=0\)
(D) \(p=-2, q=1\)

Answer 1

Ans: (A)

$$
\begin{aligned}
&2 p^{2}+q=0 \\
&q(p+q+1)=0
\end{aligned} \Rightarrow p=1, q=-2
$$