Question

The angle of incidence at which reflected light in totally polarized for reflection from air to glass (refractive index \(n\) ), is
(a) \(\sin ^{-1}(n)\)
(b) \(\sin ^{-1}(1 / n)\)
(c) \(\tan ^{-1}(1 / n)\)
(d) \(\tan ^{-1}(n)\)

Answer 1

(d) : According to Brewster's law of polarization, \(n=\) tanip where \(i_{p}\) is angle of incidence
Therefore, \(\mathrm{i}_{\mathrm{D}}=\tan ^{-1}(\mathrm{n})\).

Answer 2

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